The insurance management system is a schema of the insurance management database.
This schema consists of a database named insurancedb and various tables are created in it. These tables helps in managing all sorts of data in a systematic way.
By performing different kinds of queries we can easily extract the required data.
First, we have to create the database "insurancedb" :
mysql> CREATE DATABASE insurancedb;
After creating the database, then we have to use that database.:
USE insurancedb;
In the database we have to create different tables:
Creating table address_details
CREATE TABLE address_details
(
address_id int primary key,
h_no varchar(6),
city varchar(50),
addressline1 varchar(50),
state varchar(50),
pin varchar(50)
);
Creating table user_details
CREATE TABLE user_details
(
user_id int primary key,
firstname varchar(50),
lastname varchar(50),
email varchar(50),
mobileno varchar(50),
address_id int references address_details(address_id),
dob date
);
Creating table ref_policy_types
CREATE TABLE ref_policy_types
(
policy_type_code varchar(10) primary key,
policy_type_name varchar(50)
);
Creating table policy_sub_types
CREATE TABLE policy_sub_types
(
policy_type_id varchar(10) primary key,
policy_type_code varchar(10) references
ref_policy_types(policy_type_code),
description varchar(50),
yearsofpayements int,
amount double,
maturityperiod int,
maturityamount double,
validity int
);
Creating table user_policies
CREATE TABLE user_policies
(
policy_no varchar(20) primary key,
user_id int references user_details(user_id),
date_registered date,
policy_type_id varchar(10) references
policy_sub_types(policy_type_id)
);
Creating table policy_payments
CREATE TABLE policy_payments
(
receipno int primary key,
user_id int references user_details(user_id),
policy_no varchar(20) references user_policies(policy_no),
dateofpayment date,
amount double,
fine double
);
After creating all the tables, we have to insert records into these tables:
Insert records into the address_details table:
INSERT INTO address_details values(1, '6-21', 'hyderabad', 'kphb', 'andhra pradesh', 1254);
INSERT INTO address_details values(2, '7-81', 'chennai', 'seruseri', 'tamilnadu', 16354);
INSERT INTO address_details values(3, '3-71', 'lucknow', 'street', 'uttarpradesh', 86451);
INSERT INTO address_details values(4, '4-81', 'mumbai', 'iroli', 'maharashtra', 51246);
INSERT INTO address_details values(5, '5-81', 'bangalore', 'mgroad', 'karnataka', 125465);
INSERT INTO address_details values(6, '6-81', 'ahamadabad', 'street2', 'gujarat', 125423);
INSERT INTO address_details values(7, '9-21', 'chennai', 'sholinganur', 'tamilnadu', 654286);
Insert records into the user_details table:
INSERT INTO user_details values(1111,'raju','reddy','raju@gmail.com','9854261456',4,'1986-4- 11');
INSERT INTO user_details values(2222,'vamsi','krishna','vamsi@gmail.com','9854261463',1,'1990-4-11');
INSERT INTO user_details values(3333,'naveen','reddy','naveen@gmail.com','9854261496',4,'1985-3-14');
INSERT INTO user_details values(4444,'raghava','rao','raghava@gmail.com','9854261412',4,'1985-9-21');
INSERT INTO user_details values(5555,'harsha','vardhan','harsha@gmail.com','9854261445',4,'1992-10-11');
Insert records into the ref_policy_types table:
INSERT INTO ref_policy_types values('58934', 'car');
INSERT INTO ref_policy_types values('58539', 'home');
INSERT INTO ref_policy_types values('58683', 'life');
Insert records into the policy_sub_types table:
INSERT INTO policy_sub_types values('6893','58934','theft',1,5000,null,200000,1);
INSERT INTO policy_sub_types values('6894','58934','accident',1,20000,null,200000,3);
INSERT INTO policy_sub_types values('6895','58539','fire',1,50000,null,500000,3);
INSERT INTO policy_sub_types values('6896','58683','anandhlife',7,50000,15,1500000,null);
INSERT INTO policy_sub_types values('6897','58683','sukhlife',10,5000,13,300000,null);
Insert records into the user_policies table:
INSERT INTO user_policies values('689314',1111,'1994-4-18','6896');
INSERT INTO user_policies values('689316',1111,'2012-5-18','6895');
INSERT INTO user_policies values('689317',1111,'2012-6-20','6894');
INSERT INTO user_policies values('689318',2222,'2012-6-21','6894');
INSERT INTO user_policies values('689320',3333,'2012-6-18','6894');
INSERT INTO user_policies values('689420',4444,'2012-4-09','6896');
Insert records into the policy_payments table:
INSERT INTO policy_payments values(121,4444,'689420','2012-4-09',50000,null);
INSERT INTO policy_payments values(345,4444,'689420','2013-4-09',50000,null);
INSERT INTO policy_payments values(300,1111,'689317','2012-6-20',20000,null);
INSERT INTO policy_payments values(225,1111,'689316','2012-5-18',20000,null);
INSERT INTO policy_payments values(227,1111,'689314','1994-4-18',50000,null);
INSERT INTO policy_payments values(100,1111,'689314','1995-4-10',50000,null);
INSERT INTO policy_payments values(128,1111,'689314','1996-4-11',50000,null);
INSERT INTO policy_payments values(96,1111,'689314','1997-4-18',50000,200);
INSERT INTO policy_payments values(101,1111,'689314','1998-4-09',50000,null);
INSERT INTO policy_payments values(105,1111,'689314','1999-4-08',50000,null);
INSERT INTO policy_payments values(120,1111,'689314','2000-4-05',50000,null);
INSERT INTO policy_payments values(367,2222,'689318','2012-6-21',20000,null);
INSERT INTO policy_payments values(298,3333,'689320','2012-6-18',20000,null);
Performing Queries:
After all creating database, creating tables and then inserting records into them, we have to perform queries on these tables:
Problem#1:
Write a query to display the policytypeid,policytypename,description of all the car’s policy details.
Solution:
SELECT p.policy_type_id, r.policy_type_name, p.description FROM policy_sub_types p JOIN ref_policy_types r ON p.policy_type_code = r.policy_type_code WHERE r.policy_type_name ='car';
Problem#2:
Write a query to display the policytypecode,no of polycies in each code with alias name NO_OF_POLICIES.
Solution:
SELECT policy_type_code, COUNT(policy_type_code) no_of_policies
FROM policy_sub_types
GROUP BY policy_type_code;
Problem#3:
Write a query to display the userid,firstname,lastname, email,mobileno who are residing in Chennai.
Solution:
SELECT ud.user_id, ud.firstname, ud.lastname, ud.email, ud.mobileno
FROM user_details ud JOIN address_details ad ON ud.address_id=ad.address_id
WHERE ad.city='hyderabad'
GROUP BY ud.user_id;
Problem#4:
Write a query to display the userid, firstname lastname with alias name USER_NAME,email,mobileno who has taken the car polycies.
Solution:
SELECT ud.user_id, ud.firstname, ud.lastname user_name, ud.email, ud.mobileno
FROM user_details ud JOIN user_policies up JOIN policy_sub_types ps JOIN ref_policy_types rf ON ud.user_id=up.user_id AND up.policy_type_id=ps.policy_type_id AND ps.policy_type_code=rf.policy_type_code
WHERE rf.policy_type_name='car';
Problem#5:
Write a query to display the userid, firstname,last name who has taken the car policies but not home ploicies.
Solution:
SELECT user_id, firstname, lastname FROM USER_DETAILS WHERE USER_ID in
(SELECT USER_ID FROM USER_POLICIES where
POLICY_TYOPE_ID in
(SELECT POLICY_TYPE_ID FROM POLICY_SUB_TYPES
WHERE POLICY_TYPE_CODE=
(SELECT POLICY_TYPE_CODE FROM REF_POLICY_TYPES
WHERE POLICY_TYPE_NAME='CAR')) AND
USER_ID NOT in
(SELECT USER_ID FROM USER_POLICIES where
POLICY_TYOPE_ID in
(SELCT POLICY_TYPE_ID FROM POLICY_SUB_TYPES
WHERE POLICY_TYPE_CODE=
(SELECT POLICY_TYPE_CODE FROM REF_POLICY_TYPES
WHERE POLICY_TYPE_NAME='HOME')))) ;
Problem#6:
Write a query to display the policytypecode, policytype name which policytype has maximum no of policies.
Solution:
SELECT rf.policy_type_code, policy_type_name, COUNT(ps.policy_type_id)
FROM ref_policy_types rf JOIN policy_sub_types ps
ON rf.policy_type_code=ps.policy_type_code
GROUP BY policy_type_name
HAVING COUNT(ps.policy_type_id)=(SELECT COUNT(ps.policy_type_id) FROM policy_sub_types ps
GROUP BY ps.policy_type_code
ORDER BY COUNT(ps.policy_type_id) DESC
limit 1)OR
COUNT(ps.policy_type_id)=(select count(ps.policy_type_id) from
policy_sub_types ps
GROUP BY ps.policy_type_code
ORDER BY count(ps.policy_type_id) asc
limit 1)
ORDER BY COUNT(ps.policy_type_id);
Problem#7:
Write a query to display the userid, firtsname, lastname, city state whose city is ending with ‘bad’.
Solution:
select ud.user_id,firstname,lastname,ad.city,ad.state from
user_details ud join address_details ad on
ud.address_id=ad.address_id
where ad.city like '%bad';
Problem#8:
Write a query to display the userid, firstname, lastname ,ploicyno, dateregistered who has registered before may 2012.
Solution:
select up.user_id,firstname,lastname,policy_no, date_registered
from user_policies up join
user_details ud on
up.user_id=ud.user_id
where up.date_registered < '2012-05-01';
Problem#9:
Write a query to display the userid, firstname, lastname who has taken more than one policies.
Solution:
select ud.user_id,ud.firstname,ud.lastname from
user_details ud join
user_policies up on
ud.user_id=up.user_id
group by ud.user_id
having count(up.policy_type_id)>1;
Problem#10:
Write a query to display the policytypecode, policytypename, policytypeid, userid, ploicyno whose maturity will fall in the month of august 2013.
Solution:
select rf.policy_type_code,rf.policy_type_name,up.policy_type_id,up.user_id,up.policy_no
from ref_policy_types rf join
policy_sub_types ps join
user_policies up on
rf.policy_type_code=ps.policy_type_code and
up.policy_type_id=ps.policy_type_id
where extract(month from adddate(up.date_registered,interval ps.maturityperiod month))='7'
and extract(year from adddate(up.date_registered,interval ps.maturityperiod month))='2013';
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